Enabling the internal pull-up resistors on an ATmega8

I was having a problem setting up my atmega8 for user input. My input signal from my button (which was directly connected from my microcontroller to ground) seemed to flucuate after a change. It seems that the problem was that the ATmega8’s internal pull-up resistors weren’t enabled (these resistors cause the input signals to default to 1 when connected to nothing in particular). Figuring out how to enable these pullup resistors took a bit of doing. I found what I needed by looking at this example source code. Turns out you set the pullup resistor to on in avr-gcc by setting the PORTx bits to 1 for your input pins.

Here’s the source code that finally did what I expected:

//responsible for the uintN_t types
#include <inttypes.h>

//responsible for PORTX DDRX registers
#include <avr/io.h>

//responsible for SIGNAL macro
#include <avr/signal.h>

//responsible for sei
#include <avr/interrupt.h>

#include <avr/pgmspace.h>


int main(void)
{
	// Data Direction Register for Port D
	// 1 means output, 0 means input
	DDRD = 0xFF; //Set all pins to output
	PORTD = 0x00; // just to let us know that fun stuff is happening
	// Data Direction Register for Port B
	// 1 means output, 0 means input
	DDRC = 0x00; //Set all pins input!
        PORTC = 0xFF;  //enable pull up resistor?
	while(1){ 
        PINC = 0xFF; 
	if (~PINC & 0x01) { 
		   PORTD = 0xFF;
	}
		  else PORTD = 0x00; }
	return 1;
}

3 Comments

  1. John Carrino says:

    Busted code post++

    Try wrapping in pre tags and code tags and escaping lt, gt and amp.

  2. buffalo says:

    fixed

  3. George says:

    Try only changing the lowest four bits of your C register, the atmega8 may not have pins associated with all 8 bits in the register

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